10*a+b)^n-(10*a)^n<=c(前一步的差與本段合成);且b取最大值
10*a+b)^n-(10*a)^n<=c,即b^5<=23,且為最大值;顯然b=1 " ^$ v1 |" Z5 E0 E, c7 Y- q
10*a+b)^n-(10*a)^n<=c,即:(10+b)^5-10^5<=2201781, * x/ ^: h/ |/ t" w) i1 H6 }5 ]| 歡迎光臨 機(jī)械社區(qū) (http://m.whclglass.com.cn/) | Powered by Discuz! X3.5 |